20x^2=12x

Solution for 20x^2=12x equation:

20x^2=12x

We move all terms to the left:

20x^2-(12x)=0

a = 20; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·20·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*20}=\frac{0}{40}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*20}=\frac{24}{40}
=3/5
$